How To Solve Stoichiometry Problems Step By Step

H2 Ca(Cl O3)2 This shows that for every 2 moles of chloric acid, 1 mol of hydrogen forms.Thus, 0.207 moles chloric acid leads to 0.207/2 = 0.1036 moles hydrogen.

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We know what a chemical equation is and we've learned how to balance it.

So it's a relationship between the reactants and the products in a balanced chemical equation. Just so we get practice balancing equations, I'm always going to start with unbalanced equations. How many iron atoms do we have on the right hand side? And then we need to have twice as many moles of aluminum. This mass is going to be 2 times 56 plus 3 times 16. But this isn't a math video, so I'll get the calculator out. So in our reaction we said we're starting off with 85 grams of iron oxide. Well 85 grams of iron three oxide is equal to 85 over 160 moles. So we're going to need 1.06 moles of aluminum. So for every mole of this, we need two moles of this.

So if we're given an unbalanced one, we know how to get to the balanced point. Because for every mole of the iron three oxide, we have two moles of aluminum. So that's equal to, 85 divided by 160 equals 0.53125. So everything we've done so far in this green and light blue, we figured out how many moles 85 grams of iron three oxide is. If we have 0.53 moles, you multiply that by 2, and you have 1.06 moles of aluminum.

And we're just looking at the coefficients, we're just looking at the numbers. All right, so we just have to figure out how many grams is a mole of aluminum and then multiply that times 1.06 and we're done.

One molecule of iron three oxide combines with two molecule of aluminum to make this reaction happen. Let's say we're dealing with the version of iron, the isotope of iron, that has 30 neutrons. So aluminum, or aluminium as some of our friends across the pond might say. Aluminium has the atomic weight or the weighted average is 26.98. Or 6.02 times 10 to 23 aluminium atoms is going to be 27 grams. So we need 28.62 grams of aluminium, I won't write the whole thing there, in order to essentially use up our 85 grams of the iron three oxide.

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